SELECT FIELD1, COUNT(*) AS A FROM TABLE_NAME
WHERE RECORD_YEAR = 2007
GROUP BY FIELD1 HAVING (COUNT(FIELD1) > 1)
or to find only one occurence of a value in the field:
SELECT FIELD1, COUNT(*) AS A FROM TABLE_NAME
WHERE RECORD_YEAR = 2007
GROUP BY FIELD1 HAVING (COUNT(FIELD1) = 1)
1 comment:
sql find duplicates values in table
-sara
sql find duplicates values in table
Post a Comment